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Part III Practice Problems on
Inferential Statistics
 from www.businessbookmall.com

Formula Reviews From Quick Notes Statistics may help with these problems.
When printing, highlight just the problems and not the advertising and then choose File, Print, Section, and OK.

7) The human services manager is concerned that employee absenteeism may not be happening equally throughout the week. Using the 5-step approach to hypothesis testing, investigate her concern at the .01 level of significance.
C
ategorizing Statistics Problems will help if you do not know what test to run.
        Absences  
  Monday 12
  Tuesday 8
  Wednesday 6
  Thursday 9
  Friday 15









8) The marketing director of the We'll Be Famous Company wants to determine if age has an affect on target market acceptance of Quick Grow Finger Nail Paste. Using the 5-step approach to hypothesis testing, analyze this data at the .05 level of significance.  Categorizing Statistics Problems will help if you do not know what test to run.

Customer Attitude Toward Quick Grow Finger Nail Paste

  Would Buy Won't Buy

Totals

Age  
Under 20

45   15   60  
20 and Over 10   30   40  


 

Part II Instructions: Use two paragraphs consisting of complete sentences to define an hypothesis test related to your major.

 

 

 

 

 

 

 

 

Part III Instructions: Use at least three paragraphs consisting of complete sentences to explain a business activity of a company you are familiar with, to describe the duties of a position at this company that would be of interest to you, and to define how this company could use the 5-step approach to hypothesis testing to solve a company problem. The wording of this question is specifically designed to give wide flexibility and freedom when writing your essay.

 

 

 

 

 

 

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Answers:  


1) z of 1.75 from the data is not beyond z critical of 1.96 for the .05 level of significance (divide by 2), accept the null hypothesis, accounts receivables could equal the $375 stated on the balance sheet.


2) 1) z of 1.75 from the data is beyond z critical of 1.645 from the .05 level of significance, reject the null hypothesis, average accounts receivables could be larger than the $375 stated on the balance sheet.


3) t of 1.75 from the data is not beyond t critical of 2.064 from the .05 level of significance (divided by 2), accept the null hypothesis, accounts receivables could equal the $375 stated on the balance sheet.


4) t of 1.75 from the data is beyond t critical of 1.711 from the .05 level of significance, reject the null hypothesis, average accounts receivables could be larger than the $375 stated on the balance sheet.


5) t of -2.69 from the data is not beyond t critical of -2.977 from the .01 level of significance (divided by two), accept the null hypothesis, the time it takes to make parts does not differ for the two shifts.


6) t of -5.08 from the data is beyond t critical of -2.132 from the .05 level of significance, reject the null hypothesis, scores improved.


7) 5.0 < 13.28, accept the null hypothesis at the .01 level of significance, absences happen equally throughout the week.


8) 24.24 > 3.84, reject the null hypothesis at the .05 level of significance. There is a relationship and customer acceptance is dependent upon age.

 

Consider Quick Statistics Using Microsoft (TM) Excel
for the fastest and easiest way to do these and other statistical tests.

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